Optimal. Leaf size=194 \[ \frac {a x}{c^3 d^3}+\frac {b}{8 c^4 d^3 (1+c x)^2}-\frac {11 b}{8 c^4 d^3 (1+c x)}+\frac {11 b \tanh ^{-1}(c x)}{8 c^4 d^3}+\frac {b x \tanh ^{-1}(c x)}{c^3 d^3}+\frac {a+b \tanh ^{-1}(c x)}{2 c^4 d^3 (1+c x)^2}-\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3 (1+c x)}+\frac {3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^4 d^3}+\frac {b \log \left (1-c^2 x^2\right )}{2 c^4 d^3}-\frac {3 b \text {PolyLog}\left (2,1-\frac {2}{1+c x}\right )}{2 c^4 d^3} \]
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Rubi [A]
time = 0.19, antiderivative size = 194, normalized size of antiderivative = 1.00, number of steps
used = 18, number of rules used = 10, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6087, 6021,
266, 6063, 641, 46, 213, 6055, 2449, 2352} \begin {gather*} -\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3 (c x+1)}+\frac {a+b \tanh ^{-1}(c x)}{2 c^4 d^3 (c x+1)^2}+\frac {3 \log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3}+\frac {a x}{c^3 d^3}-\frac {3 b \text {Li}_2\left (1-\frac {2}{c x+1}\right )}{2 c^4 d^3}-\frac {11 b}{8 c^4 d^3 (c x+1)}+\frac {b}{8 c^4 d^3 (c x+1)^2}+\frac {11 b \tanh ^{-1}(c x)}{8 c^4 d^3}+\frac {b x \tanh ^{-1}(c x)}{c^3 d^3}+\frac {b \log \left (1-c^2 x^2\right )}{2 c^4 d^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 46
Rule 213
Rule 266
Rule 641
Rule 2352
Rule 2449
Rule 6021
Rule 6055
Rule 6063
Rule 6087
Rubi steps
\begin {align*} \int \frac {x^3 \left (a+b \tanh ^{-1}(c x)\right )}{(d+c d x)^3} \, dx &=\int \left (\frac {a+b \tanh ^{-1}(c x)}{c^3 d^3}-\frac {a+b \tanh ^{-1}(c x)}{c^3 d^3 (1+c x)^3}+\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (1+c x)^2}-\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^3 d^3 (1+c x)}\right ) \, dx\\ &=\frac {\int \left (a+b \tanh ^{-1}(c x)\right ) \, dx}{c^3 d^3}-\frac {\int \frac {a+b \tanh ^{-1}(c x)}{(1+c x)^3} \, dx}{c^3 d^3}+\frac {3 \int \frac {a+b \tanh ^{-1}(c x)}{(1+c x)^2} \, dx}{c^3 d^3}-\frac {3 \int \frac {a+b \tanh ^{-1}(c x)}{1+c x} \, dx}{c^3 d^3}\\ &=\frac {a x}{c^3 d^3}+\frac {a+b \tanh ^{-1}(c x)}{2 c^4 d^3 (1+c x)^2}-\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3 (1+c x)}+\frac {3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^4 d^3}-\frac {b \int \frac {1}{(1+c x)^2 \left (1-c^2 x^2\right )} \, dx}{2 c^3 d^3}+\frac {b \int \tanh ^{-1}(c x) \, dx}{c^3 d^3}+\frac {(3 b) \int \frac {1}{(1+c x) \left (1-c^2 x^2\right )} \, dx}{c^3 d^3}-\frac {(3 b) \int \frac {\log \left (\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{c^3 d^3}\\ &=\frac {a x}{c^3 d^3}+\frac {b x \tanh ^{-1}(c x)}{c^3 d^3}+\frac {a+b \tanh ^{-1}(c x)}{2 c^4 d^3 (1+c x)^2}-\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3 (1+c x)}+\frac {3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^4 d^3}-\frac {(3 b) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+c x}\right )}{c^4 d^3}-\frac {b \int \frac {1}{(1-c x) (1+c x)^3} \, dx}{2 c^3 d^3}+\frac {(3 b) \int \frac {1}{(1-c x) (1+c x)^2} \, dx}{c^3 d^3}-\frac {b \int \frac {x}{1-c^2 x^2} \, dx}{c^2 d^3}\\ &=\frac {a x}{c^3 d^3}+\frac {b x \tanh ^{-1}(c x)}{c^3 d^3}+\frac {a+b \tanh ^{-1}(c x)}{2 c^4 d^3 (1+c x)^2}-\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3 (1+c x)}+\frac {3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^4 d^3}+\frac {b \log \left (1-c^2 x^2\right )}{2 c^4 d^3}-\frac {3 b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^4 d^3}-\frac {b \int \left (\frac {1}{2 (1+c x)^3}+\frac {1}{4 (1+c x)^2}-\frac {1}{4 \left (-1+c^2 x^2\right )}\right ) \, dx}{2 c^3 d^3}+\frac {(3 b) \int \left (\frac {1}{2 (1+c x)^2}-\frac {1}{2 \left (-1+c^2 x^2\right )}\right ) \, dx}{c^3 d^3}\\ &=\frac {a x}{c^3 d^3}+\frac {b}{8 c^4 d^3 (1+c x)^2}-\frac {11 b}{8 c^4 d^3 (1+c x)}+\frac {b x \tanh ^{-1}(c x)}{c^3 d^3}+\frac {a+b \tanh ^{-1}(c x)}{2 c^4 d^3 (1+c x)^2}-\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3 (1+c x)}+\frac {3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^4 d^3}+\frac {b \log \left (1-c^2 x^2\right )}{2 c^4 d^3}-\frac {3 b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^4 d^3}+\frac {b \int \frac {1}{-1+c^2 x^2} \, dx}{8 c^3 d^3}-\frac {(3 b) \int \frac {1}{-1+c^2 x^2} \, dx}{2 c^3 d^3}\\ &=\frac {a x}{c^3 d^3}+\frac {b}{8 c^4 d^3 (1+c x)^2}-\frac {11 b}{8 c^4 d^3 (1+c x)}+\frac {11 b \tanh ^{-1}(c x)}{8 c^4 d^3}+\frac {b x \tanh ^{-1}(c x)}{c^3 d^3}+\frac {a+b \tanh ^{-1}(c x)}{2 c^4 d^3 (1+c x)^2}-\frac {3 \left (a+b \tanh ^{-1}(c x)\right )}{c^4 d^3 (1+c x)}+\frac {3 \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{c^4 d^3}+\frac {b \log \left (1-c^2 x^2\right )}{2 c^4 d^3}-\frac {3 b \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^4 d^3}\\ \end {align*}
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Mathematica [A]
time = 0.44, size = 167, normalized size = 0.86 \begin {gather*} \frac {32 a c x+\frac {16 a}{(1+c x)^2}-\frac {96 a}{1+c x}-96 a \log (1+c x)+b \left (-20 \cosh \left (2 \tanh ^{-1}(c x)\right )+\cosh \left (4 \tanh ^{-1}(c x)\right )+16 \log \left (1-c^2 x^2\right )-48 \text {PolyLog}\left (2,-e^{-2 \tanh ^{-1}(c x)}\right )+20 \sinh \left (2 \tanh ^{-1}(c x)\right )+4 \tanh ^{-1}(c x) \left (8 c x-10 \cosh \left (2 \tanh ^{-1}(c x)\right )+\cosh \left (4 \tanh ^{-1}(c x)\right )+24 \log \left (1+e^{-2 \tanh ^{-1}(c x)}\right )+10 \sinh \left (2 \tanh ^{-1}(c x)\right )-\sinh \left (4 \tanh ^{-1}(c x)\right )\right )-\sinh \left (4 \tanh ^{-1}(c x)\right )\right )}{32 c^4 d^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.34, size = 228, normalized size = 1.18
method | result | size |
derivativedivides | \(\frac {\frac {a c x}{d^{3}}-\frac {3 a \ln \left (c x +1\right )}{d^{3}}-\frac {3 a}{d^{3} \left (c x +1\right )}+\frac {a}{2 d^{3} \left (c x +1\right )^{2}}+\frac {b \arctanh \left (c x \right ) c x}{d^{3}}-\frac {3 b \arctanh \left (c x \right ) \ln \left (c x +1\right )}{d^{3}}-\frac {3 b \arctanh \left (c x \right )}{d^{3} \left (c x +1\right )}+\frac {b \arctanh \left (c x \right )}{2 d^{3} \left (c x +1\right )^{2}}-\frac {3 b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (c x +1\right )}{2 d^{3}}+\frac {3 b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (\frac {c x}{2}+\frac {1}{2}\right )}{2 d^{3}}+\frac {3 b \dilog \left (\frac {c x}{2}+\frac {1}{2}\right )}{2 d^{3}}+\frac {3 b \ln \left (c x +1\right )^{2}}{4 d^{3}}-\frac {3 b \ln \left (c x -1\right )}{16 d^{3}}+\frac {b}{8 d^{3} \left (c x +1\right )^{2}}-\frac {11 b}{8 d^{3} \left (c x +1\right )}+\frac {19 b \ln \left (c x +1\right )}{16 d^{3}}}{c^{4}}\) | \(228\) |
default | \(\frac {\frac {a c x}{d^{3}}-\frac {3 a \ln \left (c x +1\right )}{d^{3}}-\frac {3 a}{d^{3} \left (c x +1\right )}+\frac {a}{2 d^{3} \left (c x +1\right )^{2}}+\frac {b \arctanh \left (c x \right ) c x}{d^{3}}-\frac {3 b \arctanh \left (c x \right ) \ln \left (c x +1\right )}{d^{3}}-\frac {3 b \arctanh \left (c x \right )}{d^{3} \left (c x +1\right )}+\frac {b \arctanh \left (c x \right )}{2 d^{3} \left (c x +1\right )^{2}}-\frac {3 b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (c x +1\right )}{2 d^{3}}+\frac {3 b \ln \left (-\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (\frac {c x}{2}+\frac {1}{2}\right )}{2 d^{3}}+\frac {3 b \dilog \left (\frac {c x}{2}+\frac {1}{2}\right )}{2 d^{3}}+\frac {3 b \ln \left (c x +1\right )^{2}}{4 d^{3}}-\frac {3 b \ln \left (c x -1\right )}{16 d^{3}}+\frac {b}{8 d^{3} \left (c x +1\right )^{2}}-\frac {11 b}{8 d^{3} \left (c x +1\right )}+\frac {19 b \ln \left (c x +1\right )}{16 d^{3}}}{c^{4}}\) | \(228\) |
risch | \(-\frac {3 b \ln \left (c x +1\right )^{2}}{4 c^{4} d^{3}}+\left (\frac {b x}{2 c^{3} d^{3}}+\frac {-3 b \,d^{3} x -\frac {5 d^{3} b}{2 c}}{2 c^{3} d^{6} \left (c x +1\right )^{2}}\right ) \ln \left (c x +1\right )+\frac {b}{8 c^{4} d^{3} \left (c x +1\right )^{2}}-\frac {3 b}{2 c^{4} d^{3} \left (c x +1\right )}+\frac {b \ln \left (c x +1\right )}{2 c^{4} d^{3}}-\frac {b \ln \left (-c x +1\right ) x}{2 d^{3} c^{3}}+\frac {b \ln \left (-c x +1\right )}{2 d^{3} c^{4}}-\frac {b}{2 c^{4} d^{3}}+\frac {11 b \ln \left (-c x -1\right )}{16 d^{3} c^{4}}+\frac {3 b \ln \left (-c x +1\right ) x}{4 d^{3} c^{3} \left (-c x -1\right )}-\frac {3 b \ln \left (-c x +1\right )}{4 d^{3} c^{4} \left (-c x -1\right )}-\frac {b}{8 d^{3} c^{4} \left (-c x -1\right )}+\frac {b \ln \left (-c x +1\right ) x^{2}}{16 d^{3} c^{2} \left (-c x -1\right )^{2}}+\frac {b \ln \left (-c x +1\right ) x}{8 d^{3} c^{3} \left (-c x -1\right )^{2}}-\frac {3 b \ln \left (-c x +1\right )}{16 d^{3} c^{4} \left (-c x -1\right )^{2}}-\frac {3 b \ln \left (\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (-\frac {c x}{2}+\frac {1}{2}\right )}{2 d^{3} c^{4}}+\frac {3 b \ln \left (\frac {c x}{2}+\frac {1}{2}\right ) \ln \left (-c x +1\right )}{2 d^{3} c^{4}}-\frac {3 b \dilog \left (-\frac {c x}{2}+\frac {1}{2}\right )}{2 d^{3} c^{4}}+\frac {a x}{c^{3} d^{3}}-\frac {a}{d^{3} c^{4}}+\frac {3 a}{d^{3} c^{4} \left (-c x -1\right )}+\frac {a}{2 d^{3} c^{4} \left (-c x -1\right )^{2}}-\frac {3 a \ln \left (-c x -1\right )}{d^{3} c^{4}}\) | \(446\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {\int \frac {a x^{3}}{c^{3} x^{3} + 3 c^{2} x^{2} + 3 c x + 1}\, dx + \int \frac {b x^{3} \operatorname {atanh}{\left (c x \right )}}{c^{3} x^{3} + 3 c^{2} x^{2} + 3 c x + 1}\, dx}{d^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^3\,\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )}{{\left (d+c\,d\,x\right )}^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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